**Quadrilaterals** are part of a plane enclosed by four sides (quad means four and lateral means side). All quadrilaterals have exactly four sides and four angles, and they can be sorted into specific groups based on lengths of their sides or measures of their angles. What they have in common is that in every quadrilateral the sum of the measures of all interior angles is equal to .

Their vertices are marked with capital letters and sides with small letters.

Angles in vertices and are usually marked in order with: (alpha, beta, gamma, delta).

Remember that in triangles, the sum of the measures of all exterior angles is equal to (remember, exterior angle is a supplementary angle to a certain interior angle).

This will also be true for quadrilaterals. The sum of all measures of exterior angles in quadrilaterals is always equal to .

Diagonals are lines that connect opposite angles.

The division of quadrilaterals according to perpendicularity diagonals and parallel sides:

First group of quadrilaterals is a **scalene quadrilateral**. Scalene quadrilateral is a quadrilateral that doesn’t have any special properties; the sides and angles have different lengths and measures.

Quadrilaterals which have one pair of parallel sides are called **trapezoids**. Sides that are parallel are called *bases* of a trapezoid, and ones that are not parallel are called* legs*.

Trapezoids whose legs are of equal length are called **isosceles trapezoids**.

Diagonals of a isosceles trapezoids are congruent.

**Height** or **altitude **of a trapezoid is the length of a line that is perpendicular to a base and runs through opposite vertex. Altitude of a trapezoid will be equal no matter from which vertex we draw it. If we are drawing an altitude from larger base, we simply extend the shorter base.

**Theorem.**

If is an angle in vertex , in vertex , in vertex and in vertex in a trapeziod , then is valid:

.

In other words, the angles on the same side of a leg of a trapezoid are supplementary.

*Proof.*

Expand the segment over the vertices and . On the line denote point . Since the line is a transverse of the parallel lines and , then is valid . The angles and are supplementary angles, which means that .

Analogously, we obtained .

**A parallelogram** is a quadrilateral whose opposite sides are congruent and parallel.

**Altitude** or **a height** of a parallelogram, in the label , is the line segment that connects a vertex with opposite side, and is perpendicular to that side.

**Theorem**.

Let be a parallelogram. The opposite angles in a quadrilateral are congruent, and the adjacent angles are supplementary.

*Proof*.

By definition, if is a trapezoid with legs and , then:

If is a trapezoid with legs and , then:

It follows and .

**Theorem.**

The following statements are equivalent to each other:

1) A quadrilateral is a parallelogram

2) There exists two opposite sides of a quadrilateral which are congruent and parallel

3) Each two opposites sides of a quadrilateral are congruent

4) Diagonals of a quadrilateral bisect each other

5) Both pairs of opposite angles of a quadrilateral are congruent

Each of the above statements can be an alternative definition of a parallelogram. The remaining statements we need to prove.

*Proof.*

Let be a parallelogram. Then and .

Since line is a traverse of parallel lines and ,then . A line is also a traverse of parallel lines and that’s .

is also the common side of triangles and . By A-S-A theorem of congruence of triangles, triangles and are congruent. It follows that and .

In quadrilateral let be and .

Since is a traverse of the parallel lines and , that is . The side is common side of triangles and . By S-A-S theorem of congruence of triangles, triangles and are congruent. It follows that

In quadrilateral let be and , and let the point be the intersection of diagonals and .

First, consider triangles and . By S-S-S theorem of congruence of triangles, triangles and are congruent. It follows that .

Angles and are vertical angles. If now consider triangles and , it follows that . Since that triangles and are congruent by A-S-A theorem of congruence triangles. It follows that and which means that point is the midpoint of and .

In quadrilateral let the point be the midpoint of diagonals and : and .

Consider triangles and . By S-A-S theorem they are congruent ( – (vertical angles) – ). It follows that and .

Triangles and are also congruent by S-A-S theorem ( – (vertical angles) – ). It follows that and .

It follows:

and

.

In quadrilateral let be and . That means that and .

Assume that lines and are not parallel and let the point of intersection of these two lines be the point which is on the same side of line and points to and . Then angles and are interior angles of triangle , but the sum of measures of angles and is equal to , which is a contradiction.

If point is on the opposite side of line and points to and , then , which is also a contradiction.

It follows that .

Similarly we prove that .

**A ****rhombus** is a parallelogram which has at least one pair of adjacent sides of equal length.

Opposite angles are of equal measure: , and that adjacent angles are supplementary.

Diagonals in rhombus are congruent and perpendicular.

**A kite** is a quadrilateral which characterizes two pairs of sides of equal lengths that are adjacent to each other. Diagonals of a kite are perpendicular and at least one diagonal is a line of symmetry. A kite is also a tangential quadrilateral.

**A rectangle** is a parallelogram which at least one interior angle is right.

Diagonals in rectangles are congruent.

**Square** is a rectangle whose all sides are equal.

Diagonals in a square are congruent and perpendicular.

## Perimeters and areas of quadrilaterals

Perimeter of any geometric shape is the length of is outline.

Area of any geometric shape is the surface it occupies. Unit of measure for area is (square meter).

square meter is equal to the surface enclosed by a square with sides .

There are also some derived units of measure for areas, for smaller or larger shapes.

**Area of a square** is equal to a square of length of its side.

**Area of a rectangular** is equal to the product of lengths of adjacent sides.

**Area of a rhombus** is equal to the product of length of its side and altitude. This is true because, from the picture: if we translate altitude into point , and extend side over vertex , we will get triangle which is congruent with triangle . If we ‘translate’ triangle onto triangle we will get a rectangular with one side and other .

The same that goes for a rhombus works on a **parallelogram**, the area of a parallelogram is a product of its one side and altitude on that side.

Area of a trapezoid is equal to one half of a product of sum of its bases and altitude.

This formula is a result of dividing a trapezoid into a two triangles and , and a rectangle .

Now, we can write our area as the sum of smaller areas: .

We know that .

Now we need to find and . If we translate side next to we get a triangle .

The altitude of a triangle is equal to the altitude of a trapezoid .

And the side on which this altitude is set is equal to . This leads to a conclusion that:

.

This means that:

.

## Quadrilaterals worksheets

**Naming quadrilaterals** (278.7 KiB, 416 hits)

**Name the biggest number of quadrilaterals** (295.6 KiB, 339 hits)

**Angles in quadrilaterals** (423.6 KiB, 333 hits)

**Parallelograms - Find an angle** (531.7 KiB, 294 hits)

**Parallelograms - Find an length** (547.3 KiB, 286 hits)

**Trapezoids - Find a length of the median** (293.1 KiB, 316 hits)

**Trapezoids - Find a length of the half-segment** (289.9 KiB, 262 hits)

**Trapezoids - Find a length of a base** (312.8 KiB, 295 hits)

**Trapezoids - Angles** (284.8 KiB, 399 hits)

**Area of triangles and quadrilaterals** (501.9 KiB, 430 hits)