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Solving two-step inequalities on a number line

two-step inequalities

Two-step inequalities are called like that because we need to perform two steps to find the solution. They come in form:

forms of two-step inequalities

First step in solving them is the same as the one in one step inequalities. So the b goes to the other side, becomes negative self:

solving first step

Since the x is the value we are looking for, there is still something in the way. a multiplies x, so we have to deal with that before we can have our x.

Here is where you have to be careful. We have to divide our whole inequality with that a, but an inequality sign depends on whether it is negative or positive.

inequality positive sign

inequality negative sign

 

 

 

 

 

Let’s try it on a few examples:

5x + 4 < - 6

5x < - 6 - 4

5x < -10 /:5 (5 > 0, so the inequality sign remains the same)

x < -2 , x \varepsilon <-\infty, -2>

On the number line (again, since it is strictly lesser, number two isn’t included in the solution set):

number 2 is not included in number line

Example 2:

- 7x + 8 \le 1

- 7x \le 1 - 8

- 7x \le - 7

In this case x is multiplied by (-7) so we should divide it by (-7), but it is a negative number, so the inequality will change from \le to \ge .

- 7x \le -7 /:(-7)

x \ge  1, x \varepsilon [1, +\infty>

Here we have that x is greater or equal than 1. That means that x will be included in the solution set.

x will be included in number line

It would have been similar if the task was set like this:

- 7x + 8 \ge  1

- 7x \ge  1 - 8

- 7x \ge  -7 /:(-7) (we divide by a negative number
x \le 1 so the inequality changes from \ge  to \le )
Since it is less than or equal to, the number 1 is included in the solution set, which makes the solution on the number line look like this:

number 1 is included in number line

And in the form of an interval: x \varepsilon < -\infty, 1 >.

Example 3:

7x + 9 \le 1

7x \le 1 - 9

7x \le - 8 / : 7

x \le -\frac{8}{7}

-\frac{8}{7}= -1 \frac{1}{7}

inequality solution

x \varepsilon <-∞ ,-\frac{8}{7}]

Example 4:

0.2 = \frac{2}{10} = \frac{1}{5} -> 0.2x + 2 \ge  11 / * 5

\frac{1}{5}x + 2 \ge  \frac{11}{5} /* 5

x + 10 \ge  11

x \ge  11 - 10

x \ge  1
x will be included in number line

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